5(-x+2)=3+2(x+1)

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Solution for 5(-x+2)=3+2(x+1) equation: 



5(-x+2)=3+2(x+1)

We move all terms to the left:

5(-x+2)-(3+2(x+1))=0

We add all the numbers together, and all the variables

5(-1x+2)-(3+2(x+1))=0

We multiply parentheses

-5x-(3+2(x+1))+10=0



We calculate terms in parentheses: -(3+2(x+1)), so:

3+2(x+1)

determiningTheFunctionDomain
2(x+1)+3

We multiply parentheses

2x+2+3

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We get rid of parentheses

-5x-2x-5+10=0

We add all the numbers together, and all the variables

-7x+5=0

We move all terms containing x to the left, all other terms to the right

-7x=-5

x=-5/-7

x=5/7

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