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3x+4=6(x-2)-3x
We move all terms to the left:
3x+4-(6(x-2)-3x)=0
We calculate terms in parentheses: -(6(x-2)-3x), so:We get rid of parentheses
6(x-2)-3x
We add all the numbers together, and all the variables
-3x+6(x-2)
We multiply parentheses
-3x+6x-12
We add all the numbers together, and all the variables
3x-12
Back to the equation:
-(3x-12)
3x-3x+12+4=0
We add all the numbers together, and all the variables
16!=0
There is no solution for this equation
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