-4a+5(1+a)=33-6a

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Solution for -4a+5(1+a)=33-6a equation: 



-4a+5(1+a)=33-6a

We move all terms to the left:

-4a+5(1+a)-(33-6a)=0

We add all the numbers together, and all the variables

-4a+5(a+1)-(-6a+33)=0

We multiply parentheses

-4a+5a-(-6a+33)+5=0

We get rid of parentheses

-4a+5a+6a-33+5=0

We add all the numbers together, and all the variables

7a-28=0

We move all terms containing a to the left, all other terms to the right

7a=28

a=28/7

a=4

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