3(4y-1)=2(5y+1/2)=

Solution for 3(4y-1)=2(5y+1/2)= equation:

3(4y-1)=2(5y+1/2)=

We move all terms to the left:

3(4y-1)-(2(5y+1/2))=0

We add all the numbers together, and all the variables

3(4y-1)-(2(+5y+1/2))=0

We multiply parentheses

12y-(2(+5y+1/2))-3=0

We multiply all the terms by the denominator


12y*2))-(2(+5y+1-3*2))=0

We add all the numbers together, and all the variables

12y*2))-(2(5y-5))=0

We add all the numbers together, and all the variables

12y*2))-(2(5y=0

Wy multiply elements

24y^2=0

a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{48}=0$