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-4=2x^2-3x
We move all terms to the left:
-4-(2x^2-3x)=0
We get rid of parentheses
-2x^2+3x-4=0
a = -2; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·(-2)·(-4)
Δ = -23
Delta is less than zero, so there is no solution for the equation
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