(x-10)(x+14)=(x+14)(x-12)

Solution for (x-10)(x+14)=(x+14)(x-12) equation:

(x-10)(x+14)=(x+14)(x-12)

We move all terms to the left:

(x-10)(x+14)-((x+14)(x-12))=0

We multiply parentheses ..

(+x^2+14x-10x-140)-((x+14)(x-12))=0


We calculate terms in parentheses: -((x+14)(x-12)), so:

(x+14)(x-12)

We multiply parentheses ..

(+x^2-12x+14x-168)

We get rid of parentheses

x^2-12x+14x-168

We add all the numbers together, and all the variables

x^2+2x-168

Back to the equation:

-(x^2+2x-168)


We get rid of parentheses

x^2-x^2+14x-10x-2x-140+168=0

We add all the numbers together, and all the variables

2x+28=0

We move all terms containing x to the left, all other terms to the right

2x=-28

x=-28/2

x=-14