3c+9=2(12-c)

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Solution for 3c+9=2(12-c) equation: 



3c+9=2(12-c)

We move all terms to the left:

3c+9-(2(12-c))=0

We add all the numbers together, and all the variables

3c-(2(-1c+12))+9=0



We calculate terms in parentheses: -(2(-1c+12)), so:

2(-1c+12)

We multiply parentheses

-2c+24

Back to the equation:

-(-2c+24)



We get rid of parentheses

3c+2c-24+9=0

We add all the numbers together, and all the variables

5c-15=0

We move all terms containing c to the left, all other terms to the right

5c=15

c=15/5

c=3

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