-4(y+2)=2y-8+2(2y+6)

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Solution for -4(y+2)=2y-8+2(2y+6) equation: 



-4(y+2)=2y-8+2(2y+6)

We move all terms to the left:

-4(y+2)-(2y-8+2(2y+6))=0

We multiply parentheses

-4y-(2y-8+2(2y+6))-8=0



We calculate terms in parentheses: -(2y-8+2(2y+6)), so:

2y-8+2(2y+6)

determiningTheFunctionDomain
2y+2(2y+6)-8

We multiply parentheses

2y+4y+12-8

We add all the numbers together, and all the variables

6y+4

Back to the equation:

-(6y+4)



We get rid of parentheses

-4y-6y-4-8=0

We add all the numbers together, and all the variables

-10y-12=0

We move all terms containing y to the left, all other terms to the right

-10y=12

y=12/-10

y=-1+1/5

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