3(y-4)-8=-7(-2y-4)-5y

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Solution for 3(y-4)-8=-7(-2y-4)-5y equation: 



3(y-4)-8=-7(-2y-4)-5y

We move all terms to the left:

3(y-4)-8-(-7(-2y-4)-5y)=0

We multiply parentheses

3y-(-7(-2y-4)-5y)-12-8=0



We calculate terms in parentheses: -(-7(-2y-4)-5y), so:

-7(-2y-4)-5y

We add all the numbers together, and all the variables

-5y-7(-2y-4)

We multiply parentheses

-5y+14y+28

We add all the numbers together, and all the variables

9y+28

Back to the equation:

-(9y+28)



We add all the numbers together, and all the variables

3y-(9y+28)-20=0

We get rid of parentheses

3y-9y-28-20=0

We add all the numbers together, and all the variables

-6y-48=0

We move all terms containing y to the left, all other terms to the right

-6y=48

y=48/-6

y=-8

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