-3(4u-6)+7u=7(u+4)

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Solution for -3(4u-6)+7u=7(u+4) equation:



-3(4u-6)+7u=7(u+4)
We move all terms to the left:
-3(4u-6)+7u-(7(u+4))=0
We add all the numbers together, and all the variables
7u-3(4u-6)-(7(u+4))=0
We multiply parentheses
7u-12u-(7(u+4))+18=0
We calculate terms in parentheses: -(7(u+4)), so:
7(u+4)
We multiply parentheses
7u+28
Back to the equation:
-(7u+28)
We add all the numbers together, and all the variables
-5u-(7u+28)+18=0
We get rid of parentheses
-5u-7u-28+18=0
We add all the numbers together, and all the variables
-12u-10=0
We move all terms containing u to the left, all other terms to the right
-12u=10
u=10/-12
u=-5/6

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