-4(x+2)=-40x-58-5(1-5x)

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Solution for -4(x+2)=-40x-58-5(1-5x) equation: 



-4(x+2)=-40x-58-5(1-5x)

We move all terms to the left:

-4(x+2)-(-40x-58-5(1-5x))=0

We add all the numbers together, and all the variables

-4(x+2)-(-40x-58-5(-5x+1))=0

We multiply parentheses

-4x-(-40x-58-5(-5x+1))-8=0



We calculate terms in parentheses: -(-40x-58-5(-5x+1)), so:

-40x-58-5(-5x+1)

determiningTheFunctionDomain
-40x-5(-5x+1)-58

We multiply parentheses

-40x+25x-5-58

We add all the numbers together, and all the variables

-15x-63

Back to the equation:

-(-15x-63)



We get rid of parentheses

-4x+15x+63-8=0

We add all the numbers together, and all the variables

11x+55=0

We move all terms containing x to the left, all other terms to the right

11x=-55

x=-55/11

x=-5

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