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2(3x-2)=-2(1x+3)
We move all terms to the left:
2(3x-2)-(-2(1x+3))=0
We add all the numbers together, and all the variables
2(3x-2)-(-2(x+3))=0
We multiply parentheses
6x-(-2(x+3))-4=0
We calculate terms in parentheses: -(-2(x+3)), so:We get rid of parentheses
-2(x+3)
We multiply parentheses
-2x-6
Back to the equation:
-(-2x-6)
6x+2x+6-4=0
We add all the numbers together, and all the variables
8x+2=0
We move all terms containing x to the left, all other terms to the right
8x=-2
x=-2/8
x=-1/4
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