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2x-9/3=6-3/x
We move all terms to the left:
2x-9/3-(6-3/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(-3/x+6)-9/3=0
We add all the numbers together, and all the variables
2x-(-3/x+6)-3=0
We get rid of parentheses
2x+3/x-6-3=0
We multiply all the terms by the denominator
2x*x-6*x-3*x+3=0
We add all the numbers together, and all the variables
-9x+2x*x+3=0
Wy multiply elements
2x^2-9x+3=0
a = 2; b = -9; c = +3;
Δ = b2-4ac
Δ = -92-4·2·3
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{57}}{2*2}=\frac{9-\sqrt{57}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{57}}{2*2}=\frac{9+\sqrt{57}}{4} $
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