-4(v+4)=3(v+4)+

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Solution for -4(v+4)=3(v+4)+ equation:



-4(v+4)=3(v+4)+
We move all terms to the left:
-4(v+4)-(3(v+4)+)=0
We multiply parentheses
-4v-(3(v+4)+)-16=0
We calculate terms in parentheses: -(3(v+4)+), so:
3(v+4)+
We add all the numbers together, and all the variables
3(v+4)
We multiply parentheses
3v+12
Back to the equation:
-(3v+12)
We get rid of parentheses
-4v-3v-12-16=0
We add all the numbers together, and all the variables
-7v-28=0
We move all terms containing v to the left, all other terms to the right
-7v=28
v=28/-7
v=-4

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