8(z+3)-2(z-3)=2(z-1)+3(z-4)

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Solution for 8(z+3)-2(z-3)=2(z-1)+3(z-4) equation: 



8(z+3)-2(z-3)=2(z-1)+3(z-4)

We move all terms to the left:

8(z+3)-2(z-3)-(2(z-1)+3(z-4))=0

We multiply parentheses

8z-2z-(2(z-1)+3(z-4))+24+6=0



We calculate terms in parentheses: -(2(z-1)+3(z-4)), so:

2(z-1)+3(z-4)

We multiply parentheses

2z+3z-2-12

We add all the numbers together, and all the variables

5z-14

Back to the equation:

-(5z-14)



We add all the numbers together, and all the variables

6z-(5z-14)+30=0

We get rid of parentheses

6z-5z+14+30=0

We add all the numbers together, and all the variables

z+44=0

We move all terms containing z to the left, all other terms to the right

z=-44

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