2(y+1)=5(y-1)-8

Solution for 2(y+1)=5(y-1)-8 equation:

2(y+1)=5(y-1)-8

We move all terms to the left:

2(y+1)-(5(y-1)-8)=0

We multiply parentheses

2y-(5(y-1)-8)+2=0


We calculate terms in parentheses: -(5(y-1)-8), so:

5(y-1)-8

We multiply parentheses

5y-5-8

We add all the numbers together, and all the variables

5y-13

Back to the equation:

-(5y-13)


We get rid of parentheses

2y-5y+13+2=0

We add all the numbers together, and all the variables

-3y+15=0

We move all terms containing y to the left, all other terms to the right

-3y=-15

y=-15/-3

y=+5