-4(8-c)-(3c+7=)

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Solution for -4(8-c)-(3c+7=) equation: 



-4(8-c)-(3c+7=)

We move all terms to the left:

-4(8-c)-(3c+7-())=0

We add all the numbers together, and all the variables

-4(-1c+8)-(3c+7-())=0

We multiply parentheses

4c-(3c+7-())-32=0



We calculate terms in parentheses: -(3c+7-()), so:

3c+7-()

We add all the numbers together, and all the variables

3c

Back to the equation:

-(3c)



We add all the numbers together, and all the variables

c-32=0

We move all terms containing c to the left, all other terms to the right

c=32

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