-2y-4(4y+5)=3-3(-5-y)

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Solution for -2y-4(4y+5)=3-3(-5-y) equation: 



-2y-4(4y+5)=3-3(-5-y)

We move all terms to the left:

-2y-4(4y+5)-(3-3(-5-y))=0

We add all the numbers together, and all the variables

-2y-4(4y+5)-(3-3(-1y-5))=0

We multiply parentheses

-2y-16y-(3-3(-1y-5))-20=0



We calculate terms in parentheses: -(3-3(-1y-5)), so:

3-3(-1y-5)

determiningTheFunctionDomain
-3(-1y-5)+3

We multiply parentheses

3y+15+3

We add all the numbers together, and all the variables

3y+18

Back to the equation:

-(3y+18)



We add all the numbers together, and all the variables

-18y-(3y+18)-20=0

We get rid of parentheses

-18y-3y-18-20=0

We add all the numbers together, and all the variables

-21y-38=0

We move all terms containing y to the left, all other terms to the right

-21y=38

y=38/-21

y=-1+17/21

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