-4(4x-2)+8x=3+2(3x-1)

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Solution for -4(4x-2)+8x=3+2(3x-1) equation: 



-4(4x-2)+8x=3+2(3x-1)

We move all terms to the left:

-4(4x-2)+8x-(3+2(3x-1))=0

We add all the numbers together, and all the variables

8x-4(4x-2)-(3+2(3x-1))=0

We multiply parentheses

8x-16x-(3+2(3x-1))+8=0



We calculate terms in parentheses: -(3+2(3x-1)), so:

3+2(3x-1)

determiningTheFunctionDomain
2(3x-1)+3

We multiply parentheses

6x-2+3

We add all the numbers together, and all the variables

6x+1

Back to the equation:

-(6x+1)



We add all the numbers together, and all the variables

-8x-(6x+1)+8=0

We get rid of parentheses

-8x-6x-1+8=0

We add all the numbers together, and all the variables

-14x+7=0

We move all terms containing x to the left, all other terms to the right

-14x=-7

x=-7/-14

x=1/2

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