6(y+4)=-2(7y-7)+8y

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Solution for 6(y+4)=-2(7y-7)+8y equation: 



6(y+4)=-2(7y-7)+8y

We move all terms to the left:

6(y+4)-(-2(7y-7)+8y)=0

We multiply parentheses

6y-(-2(7y-7)+8y)+24=0



We calculate terms in parentheses: -(-2(7y-7)+8y), so:

-2(7y-7)+8y

We add all the numbers together, and all the variables

8y-2(7y-7)

We multiply parentheses

8y-14y+14

We add all the numbers together, and all the variables

-6y+14

Back to the equation:

-(-6y+14)



We get rid of parentheses

6y+6y-14+24=0

We add all the numbers together, and all the variables

12y+10=0

We move all terms containing y to the left, all other terms to the right

12y=-10

y=-10/12

y=-5/6

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