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1/2(2a+4)+1/3(3a-9=23
We move all terms to the left:
1/2(2a+4)+1/3(3a-9-(23)=0
Domain of the equation: 2(2a+4)!=0
a∈R
Domain of the equation: 3(3a-9-23!=0We calculate fractions
a∈R
(3a3/(2(2a+4)*3(3a-9-23)+(2a2/(2(2a+4)*3(3a-9-23)=0
We calculate terms in parentheses: +(3a3/(2(2a+4)*3(3a-9-23)+(2a2/(2(2a+4)*3(3a-9-23), so:
3a3/(2(2a+4)*3(3a-9-23)+(2a2/(2(2a+4)*3(3a-9-23
We can not solve this equation
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