-4(4v-3)+5v=5(v+4)

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Solution for -4(4v-3)+5v=5(v+4) equation: 



-4(4v-3)+5v=5(v+4)

We move all terms to the left:

-4(4v-3)+5v-(5(v+4))=0

We add all the numbers together, and all the variables

5v-4(4v-3)-(5(v+4))=0

We multiply parentheses

5v-16v-(5(v+4))+12=0



We calculate terms in parentheses: -(5(v+4)), so:

5(v+4)

We multiply parentheses

5v+20

Back to the equation:

-(5v+20)



We add all the numbers together, and all the variables

-11v-(5v+20)+12=0

We get rid of parentheses

-11v-5v-20+12=0

We add all the numbers together, and all the variables

-16v-8=0

We move all terms containing v to the left, all other terms to the right

-16v=8

v=8/-16

v=-1/2

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