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-0.7x^2-2.8x+22.4=0
a = -0.7; b = -2.8; c = +22.4;
Δ = b2-4ac
Δ = -2.82-4·(-0.7)·22.4
Δ = 70.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.8)-\sqrt{70.56}}{2*-0.7}=\frac{2.8-\sqrt{70.56}}{-1.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.8)+\sqrt{70.56}}{2*-0.7}=\frac{2.8+\sqrt{70.56}}{-1.4} $
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