-4(3y+2)-10=-6(y+5)+3y

Solution for -4(3y+2)-10=-6(y+5)+3y equation:

-4(3y+2)-10=-6(y+5)+3y

We move all terms to the left:

-4(3y+2)-10-(-6(y+5)+3y)=0

We multiply parentheses

-12y-(-6(y+5)+3y)-8-10=0


We calculate terms in parentheses: -(-6(y+5)+3y), so:

-6(y+5)+3y

We add all the numbers together, and all the variables

3y-6(y+5)

We multiply parentheses

3y-6y-30

We add all the numbers together, and all the variables

-3y-30

Back to the equation:

-(-3y-30)


We add all the numbers together, and all the variables

-12y-(-3y-30)-18=0

We get rid of parentheses

-12y+3y+30-18=0

We add all the numbers together, and all the variables

-9y+12=0

We move all terms containing y to the left, all other terms to the right

-9y=-12

y=-12/-9

y=1+1/3