4(x-2)-2(x-4)=5(x+1)-8x

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Solution for 4(x-2)-2(x-4)=5(x+1)-8x equation:



4(x-2)-2(x-4)=5(x+1)-8x
We move all terms to the left:
4(x-2)-2(x-4)-(5(x+1)-8x)=0
We multiply parentheses
4x-2x-(5(x+1)-8x)-8+8=0
We calculate terms in parentheses: -(5(x+1)-8x), so:
5(x+1)-8x
We add all the numbers together, and all the variables
-8x+5(x+1)
We multiply parentheses
-8x+5x+5
We add all the numbers together, and all the variables
-3x+5
Back to the equation:
-(-3x+5)
We add all the numbers together, and all the variables
2x-(-3x+5)=0
We get rid of parentheses
2x+3x-5=0
We add all the numbers together, and all the variables
5x-5=0
We move all terms containing x to the left, all other terms to the right
5x=5
x=5/5
x=1

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