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6x-(2x+3)=x+(2x-5)
We move all terms to the left:
6x-(2x+3)-(x+(2x-5))=0
We get rid of parentheses
6x-2x-(x+(2x-5))-3=0
We calculate terms in parentheses: -(x+(2x-5)), so:We add all the numbers together, and all the variables
x+(2x-5)
We get rid of parentheses
x+2x-5
We add all the numbers together, and all the variables
3x-5
Back to the equation:
-(3x-5)
4x-(3x-5)-3=0
We get rid of parentheses
4x-3x+5-3=0
We add all the numbers together, and all the variables
x+2=0
We move all terms containing x to the left, all other terms to the right
x=-2
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