-4(3u-1)+6u=2+2(2u-8)

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Solution for -4(3u-1)+6u=2+2(2u-8) equation: 



-4(3u-1)+6u=2+2(2u-8)

We move all terms to the left:

-4(3u-1)+6u-(2+2(2u-8))=0

We add all the numbers together, and all the variables

6u-4(3u-1)-(2+2(2u-8))=0

We multiply parentheses

6u-12u-(2+2(2u-8))+4=0



We calculate terms in parentheses: -(2+2(2u-8)), so:

2+2(2u-8)

determiningTheFunctionDomain
2(2u-8)+2

We multiply parentheses

4u-16+2

We add all the numbers together, and all the variables

4u-14

Back to the equation:

-(4u-14)



We add all the numbers together, and all the variables

-6u-(4u-14)+4=0

We get rid of parentheses

-6u-4u+14+4=0

We add all the numbers together, and all the variables

-10u+18=0

We move all terms containing u to the left, all other terms to the right

-10u=-18

u=-18/-10

u=1+4/5

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