3w2-60w+300=0

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Solution for 3w2-60w+300=0 equation: 



3w^2-60w+300=0

a = 3; b = -60; c = +300;
Δ = b2-4ac
Δ = -602-4·3·300
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{60}{6}=10$

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