X/22x-68=12+2x

Solution for X/22x-68=12+2x equation:

X/22X-68=12+2X

We move all terms to the left:

X/22X-68-(12+2X)=0


Domain of the equation: 22X!=0

X!=0/22

X!=0

X∈R


We add all the numbers together, and all the variables

X/22X-(2X+12)-68=0

We get rid of parentheses

X/22X-2X-12-68=0

We multiply all the terms by the denominator


X-2X*22X-12*22X-68*22X=0

Wy multiply elements

-44X^2+X-264X-1496X=0

We add all the numbers together, and all the variables

-44X^2-1759X=0

a = -44; b = -1759; c = 0;
Δ = b2-4ac
Δ = -17592-4·(-44)·0
Δ = 3094081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3094081}=1759$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1759)-1759}{2*-44}=\frac{0}{-88}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1759)+1759}{2*-44}=\frac{3518}{-88}
=-39+43/44
$