-4(3m+5)+6=2(1-2m)

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Solution for -4(3m+5)+6=2(1-2m) equation: 



-4(3m+5)+6=2(1-2m)

We move all terms to the left:

-4(3m+5)+6-(2(1-2m))=0

We add all the numbers together, and all the variables

-4(3m+5)-(2(-2m+1))+6=0

We multiply parentheses

-12m-(2(-2m+1))-20+6=0



We calculate terms in parentheses: -(2(-2m+1)), so:

2(-2m+1)

We multiply parentheses

-4m+2

Back to the equation:

-(-4m+2)



We add all the numbers together, and all the variables

-12m-(-4m+2)-14=0

We get rid of parentheses

-12m+4m-2-14=0

We add all the numbers together, and all the variables

-8m-16=0

We move all terms containing m to the left, all other terms to the right

-8m=16

m=16/-8

m=-2

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