3b-3b=2(b+3)+2(1+b)

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Solution for 3b-3b=2(b+3)+2(1+b) equation: 



3b-3b=2(b+3)+2(1+b)

We move all terms to the left:

3b-3b-(2(b+3)+2(1+b))=0

We add all the numbers together, and all the variables

3b-3b-(2(b+3)+2(b+1))=0

We add all the numbers together, and all the variables

-(2(b+3)+2(b+1))=0



We calculate terms in parentheses: -(2(b+3)+2(b+1)), so:

2(b+3)+2(b+1)

We multiply parentheses

2b+2b+6+2

We add all the numbers together, and all the variables

4b+8

Back to the equation:

-(4b+8)



We get rid of parentheses

-4b-8=0

We move all terms containing b to the left, all other terms to the right

-4b=8

b=8/-4

b=-2

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