-4(3+n)+4n=2(3-n)-2

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Solution for -4(3+n)+4n=2(3-n)-2 equation: 



-4(3+n)+4n=2(3-n)-2

We move all terms to the left:

-4(3+n)+4n-(2(3-n)-2)=0

We add all the numbers together, and all the variables

-4(n+3)+4n-(2(-1n+3)-2)=0

We add all the numbers together, and all the variables

4n-4(n+3)-(2(-1n+3)-2)=0

We multiply parentheses

4n-4n-(2(-1n+3)-2)-12=0



We calculate terms in parentheses: -(2(-1n+3)-2), so:

2(-1n+3)-2

We multiply parentheses

-2n+6-2

We add all the numbers together, and all the variables

-2n+4

Back to the equation:

-(-2n+4)



We add all the numbers together, and all the variables

-(-2n+4)-12=0

We get rid of parentheses

2n-4-12=0

We add all the numbers together, and all the variables

2n-16=0

We move all terms containing n to the left, all other terms to the right

2n=16

n=16/2

n=8

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