3(u-4)-2=-2(-9u+3)-9u

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Solution for 3(u-4)-2=-2(-9u+3)-9u equation: 



3(u-4)-2=-2(-9u+3)-9u

We move all terms to the left:

3(u-4)-2-(-2(-9u+3)-9u)=0

We multiply parentheses

3u-(-2(-9u+3)-9u)-12-2=0



We calculate terms in parentheses: -(-2(-9u+3)-9u), so:

-2(-9u+3)-9u

We add all the numbers together, and all the variables

-9u-2(-9u+3)

We multiply parentheses

-9u+18u-6

We add all the numbers together, and all the variables

9u-6

Back to the equation:

-(9u-6)



We add all the numbers together, and all the variables

3u-(9u-6)-14=0

We get rid of parentheses

3u-9u+6-14=0

We add all the numbers together, and all the variables

-6u-8=0

We move all terms containing u to the left, all other terms to the right

-6u=8

u=8/-6

u=-1+1/3

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