4(2r+3)=1/2(16r+24)

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Solution for 4(2r+3)=1/2(16r+24) equation: 



4(2r+3)=1/2(16r+24)

We move all terms to the left:

4(2r+3)-(1/2(16r+24))=0



Domain of the equation: 2(16r+24))!=0

r∈R



We multiply parentheses

8r-(1/2(16r+24))+12=0

We multiply all the terms by the denominator


8r*2(16r+24))-(1+12*2(16r+24))=0

Wy multiply elements

16r^2(1+24r(1=0

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