-4(3+3b)=48

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Solution for -4(3+3b)=48 equation: 



-4(3+3b)=48

We move all terms to the left:

-4(3+3b)-(48)=0

We add all the numbers together, and all the variables

-4(3b+3)-48=0

We multiply parentheses

-12b-12-48=0

We add all the numbers together, and all the variables

-12b-60=0

We move all terms containing b to the left, all other terms to the right

-12b=60

b=60/-12

b=-5

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