6(y-5)-1=-7(-4y+7)-8y

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Solution for 6(y-5)-1=-7(-4y+7)-8y equation: 



6(y-5)-1=-7(-4y+7)-8y

We move all terms to the left:

6(y-5)-1-(-7(-4y+7)-8y)=0

We multiply parentheses

6y-(-7(-4y+7)-8y)-30-1=0



We calculate terms in parentheses: -(-7(-4y+7)-8y), so:

-7(-4y+7)-8y

We add all the numbers together, and all the variables

-8y-7(-4y+7)

We multiply parentheses

-8y+28y-49

We add all the numbers together, and all the variables

20y-49

Back to the equation:

-(20y-49)



We add all the numbers together, and all the variables

6y-(20y-49)-31=0

We get rid of parentheses

6y-20y+49-31=0

We add all the numbers together, and all the variables

-14y+18=0

We move all terms containing y to the left, all other terms to the right

-14y=-18

y=-18/-14

y=1+2/7

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