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6/3x+2=2/x+1
We move all terms to the left:
6/3x+2-(2/x+1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x+1)!=0We get rid of parentheses
x∈R
6/3x-2/x-1+2=0
We calculate fractions
6x/3x^2+(-6x)/3x^2-1+2=0
We add all the numbers together, and all the variables
6x/3x^2+(-6x)/3x^2+1=0
We multiply all the terms by the denominator
6x+(-6x)+1*3x^2=0
Wy multiply elements
3x^2+6x+(-6x)=0
We get rid of parentheses
3x^2+6x-6x=0
We add all the numbers together, and all the variables
3x^2=0
a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{6}=0$
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