-4(2y-4)-y=-3(y-5)

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Solution for -4(2y-4)-y=-3(y-5) equation: 



-4(2y-4)-y=-3(y-5)

We move all terms to the left:

-4(2y-4)-y-(-3(y-5))=0

We add all the numbers together, and all the variables

-1y-4(2y-4)-(-3(y-5))=0

We multiply parentheses

-1y-8y-(-3(y-5))+16=0



We calculate terms in parentheses: -(-3(y-5)), so:

-3(y-5)

We multiply parentheses

-3y+15

Back to the equation:

-(-3y+15)



We add all the numbers together, and all the variables

-9y-(-3y+15)+16=0

We get rid of parentheses

-9y+3y-15+16=0

We add all the numbers together, and all the variables

-6y+1=0

We move all terms containing y to the left, all other terms to the right

-6y=-1

y=-1/-6

y=1/6

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