(7x-3)/10=(x+10)/4-1

Solution for (7x-3)/10=(x+10)/4-1 equation:

(7x-3)/10=(x+10)/4-1

We move all terms to the left:

(7x-3)/10-((x+10)/4-1)=0

We calculate fractions


(28x-12)/()+(-((x+10)*10)/()=0


We calculate terms in parentheses: +(-((x+10)*10)/(), so:

-((x+10)*10)/(

We multiply all the terms by the denominator


-((x+10)*10)


We calculate terms in parentheses: -((x+10)*10), so:

(x+10)*10

We multiply parentheses

10x+100

Back to the equation:

-(10x+100)


We get rid of parentheses

-10x-100

Back to the equation:

+(-10x-100)


We get rid of parentheses

(28x-12)/()-10x-100=0

We multiply all the terms by the denominator


(28x-12)-10x*()-100*()=0

We add all the numbers together, and all the variables

(28x-12)-10x*()=0

We get rid of parentheses

28x-10x*()-12=0

We move all terms containing x to the left, all other terms to the right

28x-10x*()=12