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-4(2y-1)+4y=5+2(3y-8)
We move all terms to the left:
-4(2y-1)+4y-(5+2(3y-8))=0
We add all the numbers together, and all the variables
4y-4(2y-1)-(5+2(3y-8))=0
We multiply parentheses
4y-8y-(5+2(3y-8))+4=0
We calculate terms in parentheses: -(5+2(3y-8)), so:We add all the numbers together, and all the variables
5+2(3y-8)
determiningTheFunctionDomain 2(3y-8)+5
We multiply parentheses
6y-16+5
We add all the numbers together, and all the variables
6y-11
Back to the equation:
-(6y-11)
-4y-(6y-11)+4=0
We get rid of parentheses
-4y-6y+11+4=0
We add all the numbers together, and all the variables
-10y+15=0
We move all terms containing y to the left, all other terms to the right
-10y=-15
y=-15/-10
y=1+1/2
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