6(y-3)-8=-6(-4y+3)-4

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Solution for 6(y-3)-8=-6(-4y+3)-4 equation: 



6(y-3)-8=-6(-4y+3)-4

We move all terms to the left:

6(y-3)-8-(-6(-4y+3)-4)=0

We multiply parentheses

6y-(-6(-4y+3)-4)-18-8=0



We calculate terms in parentheses: -(-6(-4y+3)-4), so:

-6(-4y+3)-4

We multiply parentheses

24y-18-4

We add all the numbers together, and all the variables

24y-22

Back to the equation:

-(24y-22)



We add all the numbers together, and all the variables

6y-(24y-22)-26=0

We get rid of parentheses

6y-24y+22-26=0

We add all the numbers together, and all the variables

-18y-4=0

We move all terms containing y to the left, all other terms to the right

-18y=4

y=4/-18

y=-2/9

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