(x-20)+(x-10)+50+(x)+30=360

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Solution for (x-20)+(x-10)+50+(x)+30=360 equation:



(x-20)+(x-10)+50+(x)+30=360
We move all terms to the left:
(x-20)+(x-10)+50+(x)+30-(360)=0
We add all the numbers together, and all the variables
x+(x-20)+(x-10)-280=0
We get rid of parentheses
x+x+x-20-10-280=0
We add all the numbers together, and all the variables
3x-310=0
We move all terms containing x to the left, all other terms to the right
3x=310
x=310/3
x=103+1/3

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