-4(-m+2)+2m=-1/2(12-12m)-3

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Solution for -4(-m+2)+2m=-1/2(12-12m)-3 equation: 



-4(-m+2)+2m=-1/2(12-12m)-3

We move all terms to the left:

-4(-m+2)+2m-(-1/2(12-12m)-3)=0



Domain of the equation: 2(12-12m)-3)!=0

m∈R



We add all the numbers together, and all the variables

-4(-1m+2)+2m-(-1/2(-12m+12)-3)=0

We add all the numbers together, and all the variables

2m-4(-1m+2)-(-1/2(-12m+12)-3)=0

We multiply parentheses

2m+4m-(-1/2(-12m+12)-3)-8=0

We multiply all the terms by the denominator


2m*2(-12m+12)-3)+4m*2(-12m-12m+12)-3)-(-1-8*2(+12)-3)=0

We add all the numbers together, and all the variables

2m*2(-12m+12)-3)+4m*2(-24m+12)-3)-(-1-8*212-3)=0

We add all the numbers together, and all the variables

-24m+2m*2(-12m+12)-3)+4m*2(=0

Wy multiply elements

4m^2(--3)-24m+4m*2(=0

We add all the numbers together, and all the variables

4m^23-24m+4m*2(=0

Wy multiply elements

4m^23+8m^2-24m=0

We do not support empression: m^23

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