4(-20j-5)=5(12-8j)

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Solution for 4(-20j-5)=5(12-8j) equation: 



4(-20j-5)=5(12-8j)

We move all terms to the left:

4(-20j-5)-(5(12-8j))=0

We add all the numbers together, and all the variables

4(-20j-5)-(5(-8j+12))=0

We multiply parentheses

-80j-(5(-8j+12))-20=0



We calculate terms in parentheses: -(5(-8j+12)), so:

5(-8j+12)

We multiply parentheses

-40j+60

Back to the equation:

-(-40j+60)



We get rid of parentheses

-80j+40j-60-20=0

We add all the numbers together, and all the variables

-40j-80=0

We move all terms containing j to the left, all other terms to the right

-40j=80

j=80/-40

j=-2

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