3/4x-7=1/2x+3

Solution for 3/4x-7=1/2x+3 equation:

3/4x-7=1/2x+3

We move all terms to the left:

3/4x-7-(1/2x+3)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x+3)!=0

x∈R


We get rid of parentheses

3/4x-1/2x-3-7=0

We calculate fractions


6x/8x^2+(-4x)/8x^2-3-7=0

We add all the numbers together, and all the variables

6x/8x^2+(-4x)/8x^2-10=0

We multiply all the terms by the denominator


6x+(-4x)-10*8x^2=0

Wy multiply elements

-80x^2+6x+(-4x)=0

We get rid of parentheses

-80x^2+6x-4x=0

We add all the numbers together, and all the variables

-80x^2+2x=0

a = -80; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-80)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-80}=\frac{-4}{-160}
=1/40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-80}=\frac{0}{-160}
=0
$