-4(-6-4x)-8x=2(8+3x)-6

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Solution for -4(-6-4x)-8x=2(8+3x)-6 equation: 



-4(-6-4x)-8x=2(8+3x)-6

We move all terms to the left:

-4(-6-4x)-8x-(2(8+3x)-6)=0

We add all the numbers together, and all the variables

-4(-4x-6)-8x-(2(3x+8)-6)=0

We add all the numbers together, and all the variables

-8x-4(-4x-6)-(2(3x+8)-6)=0

We multiply parentheses

-8x+16x-(2(3x+8)-6)+24=0



We calculate terms in parentheses: -(2(3x+8)-6), so:

2(3x+8)-6

We multiply parentheses

6x+16-6

We add all the numbers together, and all the variables

6x+10

Back to the equation:

-(6x+10)



We add all the numbers together, and all the variables

8x-(6x+10)+24=0

We get rid of parentheses

8x-6x-10+24=0

We add all the numbers together, and all the variables

2x+14=0

We move all terms containing x to the left, all other terms to the right

2x=-14

x=-14/2

x=-7

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