(-1/3)x-4=12

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Solution for (-1/3)x-4=12 equation: 



(-1/3)x-4=12

We move all terms to the left:

(-1/3)x-4-(12)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(-1/3)x-16=0

We multiply parentheses

-1x^2-16=0

a = -1; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·(-1)·(-16)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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