(3x-16)+(x+40)+(2x-5)=180

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Solution for (3x-16)+(x+40)+(2x-5)=180 equation: 



(3x-16)+(x+40)+(2x-5)=180

We move all terms to the left:

(3x-16)+(x+40)+(2x-5)-(180)=0

We get rid of parentheses

3x+x+2x-16+40-5-180=0

We add all the numbers together, and all the variables

6x-161=0

We move all terms containing x to the left, all other terms to the right

6x=161

x=161/6

x=26+5/6

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