-4(-3z-5)=-(10z+8)+2z

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Solution for -4(-3z-5)=-(10z+8)+2z equation: 



-4(-3z-5)=-(10z+8)+2z

We move all terms to the left:

-4(-3z-5)-(-(10z+8)+2z)=0

We multiply parentheses

12z-(-(10z+8)+2z)+20=0



We calculate terms in parentheses: -(-(10z+8)+2z), so:

-(10z+8)+2z

We add all the numbers together, and all the variables

2z-(10z+8)

We get rid of parentheses

2z-10z-8

We add all the numbers together, and all the variables

-8z-8

Back to the equation:

-(-8z-8)



We get rid of parentheses

12z+8z+8+20=0

We add all the numbers together, and all the variables

20z+28=0

We move all terms containing z to the left, all other terms to the right

20z=-28

z=-28/20

z=-1+2/5

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