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-3x^2-2=-46
We move all terms to the left:
-3x^2-2-(-46)=0
We add all the numbers together, and all the variables
-3x^2+44=0
a = -3; b = 0; c = +44;
Δ = b2-4ac
Δ = 02-4·(-3)·44
Δ = 528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{528}=\sqrt{16*33}=\sqrt{16}*\sqrt{33}=4\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{33}}{2*-3}=\frac{0-4\sqrt{33}}{-6} =-\frac{4\sqrt{33}}{-6} =-\frac{2\sqrt{33}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{33}}{2*-3}=\frac{0+4\sqrt{33}}{-6} =\frac{4\sqrt{33}}{-6} =\frac{2\sqrt{33}}{-3} $
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